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4x^2+1.1x-1.1=0
a = 4; b = 1.1; c = -1.1;
Δ = b2-4ac
Δ = 1.12-4·4·(-1.1)
Δ = 18.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.1)-\sqrt{18.81}}{2*4}=\frac{-1.1-\sqrt{18.81}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.1)+\sqrt{18.81}}{2*4}=\frac{-1.1+\sqrt{18.81}}{8} $
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